209k views
5 votes
1. LetXbe a uniform random variable on (0,1), and consider a counting process where eventsoccur at timesX+i, fori= 0,1,2,....(a) Does this counting process have independent increments?(b) Does this counting process have stationary increments?

1 Answer

2 votes

Answer:

(a) No.

(b) Yes.

Explanation:

(a)

Let N(t) denote the number of points on the interval [0,t].

Consider the random variables N(1/4) and N(1/2)-N(1/4).

P(N(1/4) = 1) = P(0<X≤1/4) = 1/4,

P(N(1/2)-N(1/4) = 1) = 1/4.

However,

P(N(1/4) = 1, N(1/2)-N(1/4) = 1) = 0,

as the process cannot have two points on the interval [0,1/2].

Since 0 = P(N(1/4) = 1),

P(N(1/2)-N(1/4) = 1) = 6 ≠ P(N(1/4) = 1) * P(N(1/2)-N(1/4) = 1) = 1/16,

the counting process does not have independent increments

(b)

N(s+t)-N(s) and N(t) have the same distribution.

First consider N(t). Since the distance between points in the counting process is exactly 1,

N(t) must have either [t] or [t]+1 points, where [x] is the greatest integer less than or equal to x.

Since N(t)=[t]+1 only if there is a point on the interval ([t],t)

by this the counting process have stationary increments

Hope this helps!

User Majlik
by
8.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories