Answer:
32.3 feet
Explanation:
Let BC=32 feet
AC=60.5 feet
The angle between side BC and AC=45-25=20 degrees
We have to find the distance traveled by player to get to the ball.
Cosine law:
![c^2=a^2+b^2-2ab Cos\theta](https://img.qammunity.org/2020/formulas/mathematics/college/7wg4d3q4eoiruopd3zag07wtrwk7in7gj4.png)
Using Cosine law
![c=\sqrt{(32)^2+(60.5)^2-2(32)(60.5)Cos 20^(\circ)}](https://img.qammunity.org/2020/formulas/mathematics/college/fs26zcbb7aoimhwn0x407s17to4ofdrdah.png)
![c=√((32)^2+(60.5)^2-2(32)(60.5)(0.9396))](https://img.qammunity.org/2020/formulas/mathematics/college/oxffgvlp71znnxcqn7shjemeq3odqatnv4.png)
![c=32.3 feet](https://img.qammunity.org/2020/formulas/mathematics/college/e08t5ckqb1n6tsa7wz3klpbl4jwcc5byes.png)
Hence, he travel 32.3 feet to get to the ball.