Question

The glass in a window is 35 inches wide and 20 inches tall, and standard atmospheric pressure is 14.7 pounds per square inch. What net force would result in the glass if the air pressure outside the house were 1% lower than the air pressure inside?

Answer 1

Answer:103 pounds

Step-by-step explanation:

Given

width of window
`b=35 in.`

height of window
`h=20 in.`

standard atmospheric pressure
`P_(outside)=14.7 psi`

Also
`P_(inside)=1.01P_(outside)`

Thus Net Force on the window will be the algebraic sum of Force due to outside and inside Pressure .

`F_(net)=(P_(inside)-P_(outside))\cdot A`

`F_(net)=P_(outside)(1.01-1)* 35* 20`

`F_(net)=14.7* 0.01* 35* 20`

`F_(net)=102.9\ pounds\approx 103\ pounds`