Answer:
Step-by-step explanation:
Given
Volume of fixed chamber
![V=1 m^3](https://img.qammunity.org/2020/formulas/physics/college/ojk6aohao3sm6lb580v0rf1fj9k55egn6g.png)
Initial Temperature
![T_1=300 K](https://img.qammunity.org/2020/formulas/engineering/college/8zr0gn6qct1k96kz7qzh6muy5md8dqmtd2.png)
Final Temperature
![T_2=400 K](https://img.qammunity.org/2020/formulas/physics/college/ptkk6fqgqxmp3129ze9bkhilzn10nl7lct.png)
Heat Supplied
![Q=10 J](https://img.qammunity.org/2020/formulas/physics/college/o9qn3olb9okdttn8r9udljxfp85o1mxx5j.png)
From First law of thermodynamics
Change in internal energy of the system is equal to heat added minus work done by the system
![\Delta U=Q-W](https://img.qammunity.org/2020/formulas/physics/middle-school/djrk88m6vhal5oaba5g4kvot72dvkur2ma.png)
as the volume is fixed therefore work
![W=\int PdV=0](https://img.qammunity.org/2020/formulas/physics/college/c1lmrs6zy5m3kdcj4b10x5dhrq0i55pw0k.png)
thus
![\Delta U=mc_v\Delta T=Q](https://img.qammunity.org/2020/formulas/physics/college/nxikelxhnm7tdngmgpylfaq1n1awc2izwq.png)
for mono-atomic gas is
![12.471 J/K-mol](https://img.qammunity.org/2020/formulas/physics/college/se7k4z05p040nescse9zwvh4gekigktuy6.png)
![n=0.008018 mol](https://img.qammunity.org/2020/formulas/physics/college/h2uy87xz4gtfgp5y6pxj8cxwcfxgwwdqho.png)
and 1 mole contains
![6.022* 10^(23) molecules](https://img.qammunity.org/2020/formulas/physics/college/yd1fxoxvyu7ic4psj8zd4ilj68pblesoh0.png)
thus No of molecules
![=0.008018* 6.022* 10^(23)](https://img.qammunity.org/2020/formulas/physics/college/pygntcddqtbbmhnk3nl557trc74e6xihgk.png)
No of molecules