Answer:
The period of the simple pendulum in mars = 1.60 s
Step-by-step explanation:
Period: The period of a simple pendulum is the time taken in seconds for the pendulum to complete one oscillation.
The period of a simple pendulum is
T = 2π√(L/g)............. Equation 1
making L the subject of the equation above,
L = T²g/4π²............. Equation 2
Where T = period of simple pendulum, L = length of the pendulum, g = acceleration due to gravity.
Given: T = 1.0 s,
Constant: g = 9.8 m/s², π = 3.143
Substituting these values into equation 2
L = (1²×9.8)/(4×3.143²)
L = 9.8/39.51
L = 0.248 m.
If the pendulum is taken to mars, of acceleration due to gravity = 3.8 m/s²
T = 2×3.143√(0.248/3.8)
T = 6.286√0.0653
T = 6.286×0.256
T = 1.60 s
Therefore the period of the simple pendulum in mars = 1.60 s