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The intensity of the waves from a point source at a distance d from the source is I. At what distance from the sources is the intensity equal to 2I

User Guigoz
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1 Answer

3 votes

Answer:
d'=(d)/(√(2))

Step-by-step explanation:

Intensity of the waves from a point source can be given by Power divided by surface area.

For P Power source and at a distance d from source Intensity is given by


I=(P)/(\pi\cdot d^2)--------1

when intensity is 2I then it is at a distance of let say d'


2I=(P)/(\pi\cdot d'^2)--------2

Divide 1 and 2 we get


(I)/(2I)=(P)/(\pi\cdot d^2)* (\pi\cdot d'^2)/(P)


(1)/(2)=((d')/(d))^2


(d')/(d)=(1)/(√(2))


d'=(d)/(√(2))

User Neongrau
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