Question

Suppose an 802.11 b station is configured to always reserve the channel with the RTS/CTS sequence.

Suppose this station suddenly wants to transmit 1,000 bytes of data, and all other stations are idle at this time.

As a function of SIFS and DIFS, and ignoring propagation delay and assuming no bit errors, calculate the time required to transmit the frame and receive the acknowledgment.

Answer 1

To calculate the time required to transmit the frame and receive the acknowledgment, we need to consider the time required for the RTS/CTS sequence, as well as the time required for the actual data transmission and acknowledgment. The total time can be calculated by adding the times for each step together.

Step-by-step explanation:

To calculate the time required to transmit the frame and receive the acknowledgment, we need to consider the time required for the RTS/CTS sequence, as well as the time required for the actual data transmission and acknowledgment. The sequence of events for the transmission can be broken down as follows:

1. The station sends an RTS (Request to Send) frame to the access point.
2. The access point replies with a CTS (Clear to Send) frame.
3. The station then starts transmitting the 1,000 bytes of data frame.
4. The access point receives the data frame and sends an ACK (Acknowledgment) frame.

The time required for each step can be calculated as follows:

• RTS/CTS sequence: SIFS (Short Interframe Space) + DIFS (Distributed Interframe Space)
• Data transmission: SIFS + (Time required to transmit 1,000 bytes of data)
• ACK: SIFS

Therefore, the total time required can be calculated by adding the times for each step together. The actual values of SIFS and DIFs would need to be known or given in order to calculate the exact time required.

Answer 2

Following are given the answers step by step.

I hope it will help you!

Step-by-step explanation: