Answer:
Explanation:
This can be simplified into

which is saying that you are taking the cubed root of each of those bases. The cubed root of 8 comes out evenly, to 2 (since 2*2*2 = 8). The cubed root of 320 is not so simple. To find it, find the complete factorization of 320. 320 factors to: 5 * 2*2*2*2*2*2 or
![\sqrt[3]{320}= \sqrt[3]{5*2^6}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/nktnbihbvlfdzb85a3ide3z65snjp1ssh3.png)
Split that 2^6 up into increments of 3's to make the simplifying a bit easier:
![\sqrt[3]{5*2^3*2^3}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3urcd858yf1l4jvs9km5m72ejq1lg9d2vs.png)
Because the index (the little number sitting in the bend of the radial sign) matches the power on both the 2's we can pull both the 2's out front, leaving:
![4\sqrt[3]{5}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ft3y8uy6az54ypi8eyeov9egohde9ad49k.png)
but don't forget that we already found that the cubed root of 8 was 2, so multiply that 2 by the 4 to get:
![8\sqrt[3]{5}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/o718aw5z9ul8d97loh2mfw6ngcewky20nx.png)