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A jet on an aircraft carrier can be launched from rest to 40 m/s in 2 seconds. What is the acceleration of the aircraft? Show steps please​

1 Answer

6 votes

Answer:


a=20\ m/s^2

Step-by-step explanation:

Given that,

Initial speed, u = 0

Final speed, v = 40 m/s

Time, t = 2 s

We need to find the acceleration of the aircraft. We know that, acceleration is equal to the rate of change of velocity. So,


a=(v-u)/(t)\\\\a=(40-0)/(2)\\\\=20\ m/s^2

So, the acceleration of the aircraft is
20\ m/s^2.

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