Answer:
1266,420
Explanation:
given that six women and seven men are on the faculty in a history department at a school.
women Men
6 7
To be selected 5 members
a) There should be atleast one woman
No of ways to have atleast one woman = Total ways to select 5 members - no of ways that no woman is selected
=
![13C5-7C5](https://img.qammunity.org/2020/formulas/mathematics/high-school/o2qtnu2btotd1dvwv0w4ysotet4h3w5vql.png)
(Because all members are selected from 7 men only)
= 1266
b) Exactly 3 women then no of men 2
So 3 from 6 women and 2 from 7 men to be selected
No of ways =
![6C3 (7C2)\\=(20) 21\\=420](https://img.qammunity.org/2020/formulas/mathematics/high-school/kk162dcfwbflu2xncdhja1y3cz274gtqvh.png)