Answer:
Explanation:
This is an exponential equation that is solved by taking the natural log of both sides. The equation is
![f(x)=2^x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5o7p7vymcb7ybeenmnivcuhk8mgoirr6j3.png)
If we are looking for x when f(x) = 64, then
![64=2^x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4ybk41ml0qrnaxfksqf39wls9a6mr46u88.png)
Take the natural log of both sides:
![ln(64)=ln(2^x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/l8o4vzqu4y18ty54djti1e65nvnv6d25l3.png)
The rules of logs allows us to bring the x down in front:
![ln(64)=xln(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/epda3icpwi51fdnly02lya3jzlxw0c8o0u.png)
Divide both sides by ln(2) to get:
![(ln(64))/(ln(2))=x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/sufrzzlvytf067rj5ktiit0fn304mxyux6.png)
Do this on your calculator to get that x = 6.
You could also have just gone right to your calculator and started raising 2 to consecutive powers starting at like 3 or 4 to eventually get that 2 to the 6th power is equal to 64, but for the basics of solving log equations, you need to know how to do this.