Question

a young's double plit apparatus is set up. a screen is positioned 1.6 m from the double slits and the spacing between the two slits is 0.04 mm. the distance between alternative bright fringes is 1.42 cm. find the light resourse wavelenght

Answer 1

the answer is : 3.55 ×10∧-7 m

Step-by-step explanation:

using the formula:-

delta y = (lambda)( L )/ d

GIVEN THAT;

delta y= 1.42 cm or 1.42 × 10∧-2

L = 1.6 m

d = 0.04 mm or 4 ×10∧-5

NOW rearranging the formula:-

wavelength = (delta y)(d)/L

putting the values;

wavelength = (1.42 ×10∧-2)(4×10∧-5) / 1.6

THUS;

wavelength= 3.55×10∧-7 m