Answer : The energy involved in condensation is, 339 kJ
Explanation :
Formula used :
![q=m* L](https://img.qammunity.org/2020/formulas/chemistry/college/6wujlgqmu67nk9hmp29cz8c2lq07ck6yps.png)
where,
q = heat required = ?
L = latent heat of vaporization of water =
![2.26kJ/g](https://img.qammunity.org/2020/formulas/chemistry/college/r8tk7ebsr9wjgt0bbre0o6j69rcnfo7zr0.png)
m = mass of water = 150 g
Now put all the given values in the above formula, we get:
![q=(150g)* (2.26kJ/g)](https://img.qammunity.org/2020/formulas/chemistry/college/yp0yy95tsx6077lootk1nn3w5t8wnra3gl.png)
![q=339kJ](https://img.qammunity.org/2020/formulas/chemistry/college/z3u1h34n5nlxqi2z4qwkv37hthouqivbzm.png)
Therefore, the energy involved in condensation is, 339 kJ