Final answer:
There is no solution for x in this triangle.
Step-by-step explanation:
In the triangle, we can use the cosine rule to find x. The cosine rule states that in a triangle with sides a, b, and c, and angle A opposite side a, the following equation holds: c^2 = a^2 + b^2 - 2abcos(A).
Applying the cosine rule to the triangle, we have:
8^2 = 10^2 + x^2 - 2(10)(x)cos(90).
Simplifying the equation gives:
64 = 100 + x^2 - 20x(0).
Since cos(90) = 0, the equation becomes:
64 = 100 + x^2.
Subtracting 100 from both sides gives:
-36 = x^2.
Since we're looking for a positive value for x, we can ignore the negative solution.
Taking the square root of both sides gives:
x = sqrt(-36).
Since the square root of a negative number is not a real number, there is no solution for x in this triangle.