Answer:
A. 170.24 dm³
B. 9.9 dm³
C. 80.6 dm³
Step-by-step explanation:
Data Given:
no. of moles of Ar = 7.6 mol
no. of moles of C₂H₆ = 0.44 mol
no. of moles of NH₃ = 3.6 mol
Volume of each gas at STP = ?
Solution:
To calculate volume of gas at STP (Standard temperature and pressure) formula will be used
no. of moles = volume of gas / molar Volume
Rearrange the above equation:
Volume of gas = no. of moles x molar Volume . . . . . . (1)
where
molar volume at STP = 22.4 dm³/mol
- A. Now to calculate Volume for 7.6 mole Ar
Put value in equation 1
Volume of Ar = 7.6 mol x 22.4 dm³/mol
Volume of Ar = 170.24 dm³
___________
- B. Now to calculate Volume for 0.44 mole C₂H₆
Put value in equation 1
Volume of C₂H₆ = 0.44 mol x 22.4 dm³/mol
Volume of C₂H₆ = 9.9 dm³
___________
- C. Now to calculate Volume for 3.6 mole NH₃
Put value in equation 1
Volume of NH₃ = 3.6 mol x 22.4 dm³/mol
Volume of NH₃ = 80.6 dm³