Question

How many molecules of water are there in 8.050 x 103 grams of water?

Answer 1

To find the number of water molecules in 8.050 x 10^3 grams of water, convert the mass to moles using the molar mass of water and then multiply by Avogadro's number. This yields approximately 2.69 x 10^26 molecules of water.

Step-by-step explanation:

To calculate the number of molecules of water in 8.050 x 103 grams of water, we need to first convert the mass of water to moles. Using the molar mass of water, which is approximately 18.015 g/mol, we can set up a conversion factor from grams to moles.

We divide the given mass by the molar mass of water:
8.050 x 103 g / 18.015 g/mol = 446.752 moles of water.

Now that we have the number of moles of water, we can convert this to molecules using Avogadro's number, which is 6.022 x 1023 molecules/mol. We multiply the number of moles of water by Avogadro's number:
446.752 moles x 6.022 x 1023 molecules/mol = approximately 2.69 x 1026 molecules of water.

Answer 2

2.71 × 10²⁰ molecules

Step-by-step explanation:

Given data:

Mass of water = 8.050 × 10³ g

Number of molecules = ?

Solution;

First of all we will calculate the number of moles of water,

Number of moles = mass/molar mass

Number of moles = 8.050 × 10³ g / 18 g/mol

Number of moles = 0.45 × 10³ mol

1 mole contain 6.022 × 10²³ molecules,

0.45 × 10³ mol × 6.022 × 10²³ molecules / 1 mol

2.71 × 10²⁰ molecules

The number 6.022 × 10²³ is called Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.