232,830 views
19 votes
19 votes
Could someone help me find how to extract the root from this equation?2y ^ 2 - 8 = 6 - 2y ^ 2

User Umopepisdn
by
3.0k points

1 Answer

18 votes
18 votes

Answer:

y = ± √ 7/2

Explanation:

2*y^2-8-(6-2*y^2)=0

(2 • (y2)) - 8) - (6 - 2y2) = 0

(2y2 - 8) - (6 - 2y2) = 0

Pull out like factors :

4y2 - 14 = 2 • (2y2 - 7)

4.2 Factoring: 2y2 - 7

difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2

2 • (2y2 - 7) = 0

5.1 Solve : 2 = 0

5.2 Solve : 2y2-7 = 0

Add 7 to both sides of the equation :

2y2 = 7

Divide both sides of the equation by 2:

y2 = 7/2 = 3.500

When two things are equal, their square roots are equal. Taking the square root of the two sides of the equation we get:

y = ± √ 7/2

User Salmane
by
3.0k points