Question

Info about the problems: needs to be in y = mx +b form and showing the work in detail.

thanks for the help.




1, -2x + 5y =10

2, -x - 3y = -21

3, 2y - 4x = -12
​

Answer 1

`\huge\boxed{y=(2)/(5)x+2}\ \boxed{y=-(1)/(3)x+7}\ \boxed{y=2x-6}`

To solve each of these problems, we need to find
`y`.

Problem 1

`-2x+5y=10`

Add
`2x` to both sides of the equation. Our goal is to get
`y` by itself.

`5y=2x+10`

Divide everything by
`5`.

`\boxed{y=(2)/(5)x+2}`

Problem 2

`-x-3y=-21`

Add
`x` to both sides of the equation.

`-3y=x-21`

Divide everything by
`-3`.

`\displaystyle y=-(x)/(3)+7`

Separate
`-(x)/(3)` into a coefficient and a variable.

`\boxed{y=-(1)/(3)x+7}`

Problem 3

`2y-4x=-12`

Add
`4x` to both sides of the equation.

`2y=4x-12`

Divide everything by
`2`.

`\boxed{y=2x-6}`