Question

A 55-kg woman is wearing high heels.

If each heel has a circular cross-section 6.0 mm in diameter and she puts all her weight on one heel, how much pressure does that exert on the floor?

a)4.9 x 105 Pa

b)1.9 x 10 Pa

c)4.8 x 106 Pa

d)1.9 x 105 Pa

e)1.2 x 105 Pa

Answer 1

Pressure,
`P=1.90* 10^7\ Pa`

Step-by-step explanation:

It is given that,

Mass of the woman, m = 55 kg

Diameter of the circular cross section, d = 6 mm

Radius, r = 3 mm = 0.003 m

Let P is the pressure exerted on the floor. It is equal to the force acting on woman per unit area. It is given by :

`P=(F)/(A)`

`P=(mg)/(\pi r^2)`

`P=(55* 9.8)/(\pi (0.003)^2)`

`P=1.90* 10^7\ Pa`

So, the pressure exerted on the floor is
`1.90* 10^7\ Pa`. Hence, this is the required solution.