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A hydraulic press has one piston of diameter 2.0 cm and the other piston of diameter 16.0 cm. What force must be applied to the smaller piston to obtain a force of 3200 N at the larger piston?

User Kabal
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2 Answers

3 votes

Final answer:

To calculate the force required on the smaller piston to obtain a force of 3200 N at the larger piston in a hydraulic press, we can use Pascal's law and the formula P1A1 = P2A2. By rearranging the formula and substituting the given values, we can calculate the force applied to the smaller piston.

Step-by-step explanation:

The force required on the smaller piston to obtain a force of 3200 N at the larger piston in a hydraulic press can be calculated using Pascal's law which states that the pressure applied to an enclosed fluid is transmitted undiminished to all parts of the fluid and to the walls of its container.

Pascal's law can be expressed as:

P1A1 = P2A2

Where P1 is the pressure at the smaller piston, A1 is the area of the smaller piston, P2 is the pressure at the larger piston, and A2 is the area of the larger piston.

Given that the diameter of the smaller piston is 2.0 cm and the diameter of the larger piston is 16.0 cm, we can calculate the areas of the pistons as:

A1 = π(r1^2) = π(1.0^2) = 3.14 cm^2

A2 = π(r2^2) = π(8.0^2) = 200.96 cm^2

Since P2 is given as 3200 N, we can rearrange the equation to solve for P1:

P1 = (P2A2) / A1

P1 = (3200 N * 200.96 cm^2) / 3.14 cm^2

P1 = 200,960 N/cm^2

Therefore, the force required on the smaller piston to obtain a force of 3200 N at the larger piston is:

Force = P1 * A1 = 200,960 N/cm^2 * 3.14 cm^2

Force = 631,446.4 N

User Francois Stock
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2 votes

Answer:

The force applied to the smaller piston = 2512 N

Step-by-step explanation:

Hydraulic press: A hydraulic press is a device used to produce a very large force. A hydraulic force operates based on pascal's principle.

F/f = A/a................ Equation 1

making f the subject of the equation above

f =(F×a)/A............. Equation 2

Where F = Force on the larger piston, f = force on the smaller piston, A = area of the larger piston, a = area of the smaller piston.

Given: F = 3200 N, and

Area (A) = πD²/4 where D = 16.0 cm = 0.16 m

A = 3.143×(0.16)²/4 = 0.02 m²

Also

a = πd²/4 where d = 2 cm = 0.02 cm

a = 3.143×(0.02)²/4

a = 0.0157 m²

Substituting these values into equation 2

f = (3200×0.0157)/0.02

f = 2512 N

The force applied to the smaller piston = 2512 N

User Bruvio
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