Total cost of canvas required in making the tent is rupees 79128
Solution:
Given:
Height of the cylindrical tent = h = 3.3 m
Diameter of it's base = d = 100m
r = 50 m
Curved surface area of cylinder:
![C.S.A = 2 \pi rh](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rclo7tp4t4hm6toop01jz3s36i5a8hv0zr.png)
![C.S.A = 2 * 3.14 * 50 * 3.3 = 1036.2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ztkcjswgkak35xaziya9nxm3h8iefctgpl.png)
Thus Curved surface area of cylinder = 1036.2 square meter
Curved surface area of cone:
![C.S.A = \pi rl](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8bjf98t7fv4hvm7h2hefqr4zj2sdqa4cgh.png)
![C.S.A = 3.14 * 50 * 56.4 = 8854.8](https://img.qammunity.org/2020/formulas/mathematics/middle-school/g8r8iukxv06xgw5a95dz5hgjie5a9s5jjk.png)
Thus Curved surface area of cone = 8854.8 square meter
Total curved area of tent:
⇒ curved area of cone + curved area of cylinder
![\rightarrow 8854.8 + 1036.2=9891](https://img.qammunity.org/2020/formulas/mathematics/middle-school/nz3xzas1krjiv1vwmvskif2a4pwan1fajo.png)
Thus total curved area of tent = 9891 square meter
find total cost of canvas required in making the tent:
The cost of canvas is 8 rupees per square meter
![\rightarrow \text{total cost } = 9891 * 8 = 79128](https://img.qammunity.org/2020/formulas/mathematics/middle-school/52ng19i4c6awguy5n5ymwoosmo2dad95mt.png)
Thus total cost of canvas required in making the tent is rupees 79128