Question

Elle is pushing a box of mass 7.0 kilograms with the force of 25 newtons. If the force of friction is 2.6 newtons, what is the value of acceleration of the box?​

Answer 1

the acceleration of the box is 3.2[m/s^2]

Step-by-step explanation:

This problem can be solved using the second law of movement, described by Newton. Which says that the sum of forces on a body must be equal to the product of its mass by the acceleration of it if the body is not in static equilibrium. Therefore:

`F-f=m*a\\where:\\F=25[N]\\f=2.6[N]\\m= 7[kg]\\replacing:\\25-2.6=7*a\\a=3.2[m/s^2]`

Note: the only force that is opposite to the movement is the friction force, therefore, this force takes the minus sign