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Find the value of x^3 + y^3 – 12xy + 64 when x + y = (-4)

1 Answer

3 votes

Answer:

0

Explanation:

Using the algebraic expansion

x³ + y³ = (x + y)³ - 3xy(x + y)

Given

x³ + y³ - 12xy + 64

= (x + y)³ - 3xy(x + y) - 12xy + 64

Substitute x + y = - 4 into the expression

= (- 4)³ - 3xy(- 4) - 12xy + 64

= - 64 + 12xy - 12xy + 64

= 0

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