Question

Jake and each of his brothers choose a fraction between 0 and 1.Jake chooses 3/4,Aaron chooses 9/10, and Simon choses 4/12. Which is a group of fractions that includes an equivalent fraction for each of the fractions 3/4,9/10, and 4/12? a. 3/8, 9/100, 1/4 b. 3/8, 90/100, 1/3 c. 9/12, 90/100,1/3 d. 9/12, 90/100, 1/4

Answer 1

c. 9/12, 90/100,1/3

Explanation:

3/4, *3=9/12

9/10 *10 =90/100

4/12 divided into 4 = 1/3

Answer 2

Option C.

Explanation:

It is given that Jake chooses 3/4, Aaron chooses 9/10, and Simon chooses 4/12.

We need to find the group of fractions that includes an equivalent fraction for each of the fractions 3/4,9/10, and 4/12.

Equivalent fraction:

`(a)/(b)\equiv (ka)/(kb)`

where, k is a constant.

The given fracions can be rewritten as

`(3)/(4)=(3)/(4)* (3)/(3)=(9)/(12)`

`(9)/(10)=(9)/(10)* (10)/(10)=(90)/(100)`

`(4)/(12)=(1* 4)/(3* 4)=(1)/(3)`

The equivalent fraction for each of the fractions 3/4,9/10, and 4/12 are 9/12, 90/100,1/3 respectively.

Therefore, the correct option is C.