Question

Write an equation in slope-intercept form for the line that passes through (1, 1), and is perpendicular to the graph of 3x + 2y = -7

Answer 1

y=2/3x+1/3

Explanation:

3x+2y=-7

y= -3/2x-7

slope is 2/3x

y-1=2/3(x-1)

so , y= 2/3x+1/3

Answer 2

2X-3Y = -1

Explanation:

given equation is 3X +2Y = -7

FIRST BRING THIS IN SLOPE INTERCEPT FORM

2Y = -3X -7

DIVIDING EACH TERM BY 2

Y = (-3/2)X -7/2

SLOPE OF GIVEN EQUATION IS -3/2

SLOPE OF LINE PERPENDICULAR TO THIS IS NEGATIVE RECIPROCAL HENCE SLOPE OF REQUIRED EQUATION IS 2/3

EQUATION OF STRAIGHT LINE IN POINT SLOPE FORM IS

Y-Y1 = m(X-X1)

Y-1 = (2/3)(X-1)

MULTIPLYING ALL TERMS BY 3

3(Y-1) = 2(X-1)

3Y-3 = 2X -2

2X-2 = 3Y-3

2X-3Y =-3+2

2X-3Y = -1