Answer:
A. V Ar = 185.7136 L
B. V C2H6 = 10.752 L
C. V NH3 = 87.97 L
Step-by-step explanation:
STP:
∴ T = 25°C ≅ 298 K
∴ P = 1 atm
assuming ideal gas:
⇒ V = RTn / P
∴ R = 0.082 atm.L/K.mol
A. n Ar = 7.6 mol
⇒ V Ar = ((0.082 atm.L/K.mol)(298 K)(7.6 mol)) / (1 atm) = 185.7136 L
B. n C2H6 = 0.44 mol
⇒ V = 10.752 L
C. n NH3 = 3.6 mol
⇒ V = 87.97 L