Question

Someoneee pleaseee helppp!!!

Answer 1

`part\ a\ A'(1,2),\ B'(2,5),\ C'(5,2)`

`part\ b\ A`

Explanation:

Given co-ordinates are
`A(-5,2),\ B(-4,5),\ C(-1,2).`

Part a

We will find the co-ordinate of ABC by translating 6 units to the right.

If any co-ordinate say
`P(x,y)` is translated
`k` units to the right then co-ordinate of translated point
`P'` will be
`P'(x+k,y)`

Here we are translating 6 units to the right. So, our
`k` is 6.

Now, co-ordinates after translating is

`A(-5,2)\ =\ A(-5+6,2)\ =\ A'(1,2)\\B(-4,5)\ =\ B(-4+6,5)\ =\ B'(2,5)\\C(-1,2)\ =\ C(-1+6,2)\ =\ C'(5,2)`

Part b

Now, we will find the co-ordinate of ABC after translating 6 units to the right with a rotation of 90°.

When any point say
`R'(x,y)` is rotated 90° the new co-ordinate after rotation about the origin is
`R''(-y,x)`.

So, new co-ordinates are

`A'(1,2)=A''(-2,1)\\\ B'(2,5)=B`