Answer:
For 1: The number of moles of ethanol are 11.04 moles
For 2: The volume of chlorine gas at STP for given amount is 33.6 L
Step-by-step explanation:
To calculate the number of moles, we use the equation:
![\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}](https://img.qammunity.org/2020/formulas/chemistry/high-school/gwh5prgbdt4s2p8o8xquycz897bwt6lvw1.png)
Given mass of ethanol = 508 g
Molar mass of ethanol = 46 g/mol
Putting values in above equation, we get:
![\text{Moles of ethanol}=(508g)/(46g/mol)=11.04mol](https://img.qammunity.org/2020/formulas/chemistry/middle-school/i6wq7e77g3jp8nf5sjgt18p6atcx5lp4b9.png)
Hence, the number of moles of ethanol are 11.04 moles
We are given:
Moles of chlorine gas = 1.50 moles
At STP:
1 mole of a gas occupies 22.4 L of volume
So, 1.50 moles of chlorine gas will occupy =
of volume
Hence, the volume of chlorine gas at STP for given amount is 33.6 L