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A child has a toy tied to the end of a string and whirls the toy at constant speed in a horizontal circular path of radius R. The toy completes each revolution of its motion in a time period T. What is the magnitude of the acceleration of the toy?a. g

b. 2πg
c. Zero
d. 4π²R/T²
e. πR/T²

User Rodriguez
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1 Answer

6 votes

Answer:

d.
(4\pi^(2) R)/(T^(2))

Step-by-step explanation:


R = Radius of the circular path


T = Time period of motion


w = Angular speed of the motion

Angular speed of the motion is given as


w = (2\pi )/(T)

The toy is moving in a circle and hence centripetal acceleration acts on it which can be given as


a = R w^(2) \\a = R ((2\pi )/(T))^(2)\\a = (4\pi^(2) R)/(T^(2))

hence the correct choice is

d.
(4\pi^(2) R)/(T^(2))

User BigHeadCreations
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