Answer:
a) E = 4.626 10⁻¹⁹ J , b) # = 8.86 10¹⁹ photons , c) σ = 5.83 10²² photon / m², d) # photon = 3.078 10¹⁹ photons , e) # photon = 3.078 10¹⁹ photon / s , f) The number of photons increases
Step-by-step explanation:
a) For this part let's use the Planck equation
E = h f
The speed of light is
c = λ f
We replace
E = h c /λ
Let's reduce to SI units
λ = 430 nm (1m / 10⁹ nm) = 430 10⁻⁹ nm
E = 6.63 10⁻³⁴4 3 10⁸ / 4.30 10⁻⁷
E = 4.626 10⁻¹⁹ J
b) the defined power
P = W / t = E / t
Let's look for the energy of the beam in 1 s
E = P t
E = 41 1 = 41 J
Now let's use a rule of proportions (rule of three) if 1 photon has an energy E₀ how many photons has an energy E
#photons = E / E₀ 1 photon
# photon = 41 / 4,626 10⁻¹⁹
# = 8.86 10¹⁹ photons
c) The radius of the beam is
r = 2 h
r = 2 0.011
r = 0.022 m
Density is
σ = # Photons / A
The area of a circle is
A = π R²
σ. = # Photon /π r²
σ = 8.86 1019 /π 0.022²
σ = 5.83 10²² photon / m²
d) let's look for the opening area
A₁ = l a
A₁ = 0.0048 0.011
A₁ = 5.28 10⁻⁴ m²
Let's use the density decision
σ = # Photons / A
# photon =σ . A1
# photon = 5.83 10²² 5.28 10⁻⁵
# photon = 3.078 10¹⁹ photons
e) let's look for the time it takes for photons to reach the screen.
The number of photons is the amount of photons per unit of bone time is equivalent to a speed
v = # photon = d / t
t = d / # foton
t = 0.36 / 3.078 10¹⁹
t = 1.17 10⁻²⁰ s
As there are no photons reflected on the screen, everything is absorbed, so the number of photons that enter is equal to the number of photons that are absorbed, therefore, the amount of photons does not change
# photon = 3.078 10¹⁹ photon / s
f) If the speed of the photons decreases in the space between the aperture and the screen, an imbalance is created
More photons enter than are absorbed, so the number of photons increases the region. In order to calculate this number, the index of refraction of the medium or the speed of supply of this medium must be granted.
The number of photons increases