A gas expands from an initial volume of 30.0 L to a final volume of 65.0 L at a constant pressure of 110kPa. How much work is done by the gas?

Question

asked Mar 14, 2020 134k views

1 Answer

Mike Murphy · Answer 1 · 2020-03-19T17:09:49+0000

Answer:

3850 J

Step-by-step explanation:

V_(i) = initial volume of the gas = 30 L = 0.03 m³

V_(f) = final volume of the gas = 65 L = 0.065 m³

= Constant pressure of the gas = 110 kPa = 110000 Pa

= Work done by the gas

Since the pressure is constant, Work done by the gas is given as

$W = P (V_(f) - V_(i))\\W = (110000) (0.065 - 0.03)\\W = 3850 J$