Answer:
Final speed of both the cars, V = 3.28 km/h
Step-by-step explanation:
It is given that,
Mass of the railway car,

Initial speed of the railway car,

Mass of another car,

Initial speed of another car,

To find,
The speed of the coupled cars after the collision.
Solution,
It is a case of inelastic collision in which the linear momentum before and after the collision remains same. Let V is the coupled velocity of both of the cars. So,




V = 1.011 m/s
or
V = 3.28 km/h
So, the speed of the coupled cars after the collision is 3.28 km/h. Hence, this is the required solution.