Question

A stone of density 5500 kg/m3 is submerged in water. If the volume of the stone is 0.25 m3, the mass of water it displaces is____________.

Answer 1

The mass of water displaced by the submerged stone is 250 kg, which is calculated using the stone's volume of 0.25 m³ and the known density of water.

Step-by-step explanation:

The mass of water displaced by a submerged stone is determined by the volume of the stone and the density of water. Given the density of water (1.000×10³ kg/m³) and the volume of the stone (0.25 m³), we use the formula m = ρV to find the mass of the water displaced. Therefore, the mass of water displaced by the stone when submerged is calculated as:

m = (1.00×10³ kg/m³) × (0.25 m³) = 250 kg.

Since the volume of the stone and the density of the water are known, we can conclude that when the stone is submerged, it displaces a mass of water equivalent to 250 kg.

Answer 2

Let us use the principle given in the relation of density as a function of mass and volume, but this time we will reorganize it in terms of mass so that said displaced mass is equivalent to the density of water by the volume of the stone , So,

`\rho = (m)/(V) \rightarrow m = \rho V`

Where,

`\rho`= Density

m = mass

V = Volume

Replacing,

m = 5500*0.25

m = 1375kg

Therefore the mass of water it displaces is 1375kg