Answer:
d. -y direction
Step-by-step explanation:
Given that
m₁=0.145 kg, u₁=2.1 j m/s
m₂= 0.0570 kg , u₂ = -8.8 j m/s
We know that linear momentum is the product of mass and velocity
P= Mass x velocity
Therefore the total linear momentum P
P= m₁u₁+ m₂u₂
Now by putting the values
P = 0.145 x ( 2.1 j) + 0.057 ( - 8.8 j) kg.m/s
P =0.3045 j - 0.5016 j kg.m/s
P= - 0.1971 j kg.m/s
P= 0.1971 (- j) kg.m/s
So we can say that the direction of the liner momentum of the system will be in the negative y -direction.
d. -y direction