86.3k views
3 votes
What is the equilibrium constant of pure water at 25°C?

2 Answers

3 votes

Answer:

10↑-14

Step-by-step explanation:

User Ajitkumar
by
5.4k points
4 votes

Answer: 1.0 × 10-14

Step-by-step explanation:

Pure water, represented as

H2O --> [H+] + [OH -]

undergoes a reversible reaction in which both H+ and OH- are generated.

The equilibrium constant for this reaction, called the water dissociation constant, Kw, is 1.0 × 10-14 at 25 °C.

User Truthseeker
by
5.9k points