Question

A solid cylinder with a radius of 10 cm and a mass of 3.0 kg is rotating about its center with anangular speed of 3.5 rad/s. What is its kinetic energy?

Answer 1

kE=0.0735 J

Step-by-step explanation:

Given that

Radius ,R=10 cm = 0.1 m

Mass ,m= 3 kg

Angular speed ,ω = 3.5 rad/s

We know that moment of inertia for solid sphere given as

`I=(2)/(5)mR^2`

Kinetic energy

`KE=(1)/(2)I\omega^2`

Now by putting the values

`KE=(1)/(2)* (2)/(5)mR^2* \omega^2`

`KE=(1)/(2)* (2)/(5)* 3* 0.1^2* 3.5^2\ J`

kE=0.0735 J

Therefore the kinetic energy will be 0.0735 J