Answer:
The expression of the perpendicular vector to vector A and B, been A = (a₁ , a₂ , a₃) and B = ( b₁ , b₂ , b₃ ), is ( a₂b₃ -a₃b₂ , a₃b₁ -a₁b₃ , a₁b₂- a₂b₁) in a three dimensional space.
The expresion for the perpendicular vector of A = (a₁,a₂) in 2D is (1, -a₁/a₂)
Step-by-step explanation:
If you want a perpendicular vector to another two known ones, been in a three-dimensional Cartesian coordinate system, you have to make a cross product between the 2 known vectors:
![A\wedge B=Det\left[\begin{array}{ccc}X&Y&Z\\a1&a2&a3\\b1&b2&b3\end{array}\right]](https://img.qammunity.org/2020/formulas/physics/college/dhoivapwb8elyxx21orzzqxixagwmygwq1.png)
If you want a perpendicular vector to another known one, been in a two-dimensional Cartesian coordinate system, you can propose a vector B=(1,z) and consider than Dot product A·B = 0. Therefore:
