Question

To measure moderately low pressures, oil with a density of 9.0 x 102 kg/m3 is used in place of mercury in a barometer. A change in the height of the oil column of 1.5 mm indicates a change in pressure of about:

Answer 1

Δ P = 13.24 Pa

Step-by-step explanation:

Given that

Density of oil ,ρ₁ = 9 x 10² kg/m³

We know that density for mercury ,ρ₂ = 13.6 x 10³ kg/m³

The change in the height of column ,Δh = 1.5 mm

The pressure given as

P = ρ g h

Change in the pressure

Δ P = ρ₁ g Δh

Now by putting the values

Δ P = 9 x 10² x 9.81 x 1.5 x 10⁻³ Pa

Δ P = 13.24 Pa

Therefor the change in the pressure will be 13.24 Pa.