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A certain clay cube has volume 64 cubic inches. If a smaller clay cube is formed and has half the volume of the original cube, how many inches long is an edge of the smaller cube?A. 2

B. 4
C. 8
D.
\sqrt[3]{4}
E. 2
\sqrt[3]{4}

1 Answer

2 votes

Answer:

E.
2\sqrt[3]{4}\text{ in}

Explanation:

Let a represent side length of the smaller cube.

We have been given that a certain clay cube has volume 64 cubic inches.

We will use volume of cube formula to answer our given problem.


\text{Volume of cube}=\text{Side length}^3


64\text{ in}^3=\text{Side length}^3

Since the smaller clay cube has half the volume of the original cube. So volume of smaller cube would be:


\frac{64\text{ in}^3}{2}=32\text{ in}^3

Upon substituting our given values in volume formula, we will get:


32\text{ in}^3=a^3

Switch sides:


a^3=32\text{ in}^3

Take cube root of both sides:


\sqrt[3]{a^3}=\sqrt[3]{32\text{ in}^3}


a=\sqrt[3]{4* 8\text{ in}^3}


a=\sqrt[3]{4}* \sqrt[3]{8\text{ in}^3}


a=\sqrt[3]{4}* \sqrt[3]{2^3\text{ in}^3}


a=\sqrt[3]{4}* 2\text{ in}


a=2\sqrt[3]{4}\text{ in}

Therefore, the side length of the smaller cube is
2\sqrt[3]{4}\text{ in} and option E is the correct choice.

User Tom Marthenal
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