Question

What is the pressure on a horizontal surface with an area of 8 msquared that is 4 m​ underwater? Use 1000 kg divided by m cubed for the density of water and 9.8 m divided by s squared for the acceleration due to gravity. What is the correct relationship to use to find the pressure on the horizontal​ surface?

Answer 1

140525 pa

Step-by-step explanation:

`h` = depth of water = 4 m

`A` = Area of surface = 8 m²

`\rho` = Density of water = 1000 kg m⁻³

tex]g[/tex] = acceleration due to gravity = 9.8 ms⁻²

`P_(o)` = Atmospheric pressure = 101325 Pa

`P` = Pressure at the given depth "h"

Pressure at the given depth is given as

`P = P_(o) + \rho g h\\P = 101325 + (1000) (9.8) (4)\\P = 140525 pa`