Answer:
2.56 × 10⁻³ mol
5.17 × 10⁻³ g
Step-by-step explanation:
Given data
Temperature = 35°C + 273 = 308 K
Pressure = 725 mmHg
Volume = 72.0 mL = 0.0720 L
The vapor pressure of water at 35°C is 42.20 mmHg. The total pressure is equal to the sum of the partial pressures.
P = pH₂ + pH₂O
pH₂ = P - pH₂O = 725 mmHg - 42.20 mmHg = 683 mmHg
pH₂ = 683 mmHg × (1 atm / 760 mmHg) = 0.899 atm
We can find the moles of H₂ using the ideal gas equation.
P × V = n × R × T
0.899 atm × 0.0720 L = n × (0.08206 atm.L/mol.K) × 308 K
n = 2.56 × 10⁻³ mol
The molar mass of H₂ is 2.02 g/mol. The mass of H₂ is:
2.56 × 10⁻³ mol × 2.02 g/mol = 5.17 × 10⁻³ g