Question

A 50.0-kg crate is being pulled along a horizontal smooth surface. The pulling force is 10.0 N and is directed 20.0° above the horizontal. What is the magnitude of the acceleration of the crate?a. 250 N, 0.0684 m/s²

b. 487 N, 0.188 m/s²
c. 525 N, 0.200 m/s²
d. 825 N, 0.376 m/s²
e. 494 N, 0.0728 m/s²

Answer 1

Answer:
`b-0.188 m/s^2`

Step-by-step explanation:

Given

mass of crate
`m=50 kg`

Magnitude of friction
`F=10 N`

Inclination of Force
`\theta =20^(\circ)`

Force cos component will move the Block

`F_(net)=F\cos \theta =ma`

`a=(10\cos 20)/(50)`

`a=0.188 m/s^2`