Answer: OPTION A.
Explanation:
Given the following function:
![h(x)=-(1)/(4)x^2+(1)/(2)x+(1)/(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/v85ymb8ilgz2suyvqfkjyowcjkwro44ivi.png)
You know that it represents the the height of the ball (in meters) when it is a distance "x" meters away from Rowan.
Since it is a Quadratic function its graph is parabola.
So, the maximum point of the graph modeling the height of the ball is the Vertex of the parabola.
You can find the x-coordinate of the Vertex with this formula:
![x=(-b)/(2a)](https://img.qammunity.org/2020/formulas/mathematics/college/h04sw6r4c6bv9gj7zipt5c1gmb3qbez2n6.png)
In this case:
![a=-(1)/(4)\\\\b=(1)/(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/prentynkw4u8q21t95mcunnebvfajxfat4.png)
Then, substituting values, you get:
![x=(-(1)/(2))/((2)(-(1)/(4))))\\\\x=1](https://img.qammunity.org/2020/formulas/mathematics/high-school/av90xru7n2ll8bngiu5efmn7xz379ol2tq.png)
Finally, substitute the value of "x" into the function in order to get the y-coordinate of the Vertex:
Therefore, you can conclude that:
The maximum height of the ball is 0.75 of a meter, which occurs when it is approximately 1 meter away from Rowan.