Answer:
![2HCl + CaCO_3 ---> CaCl_2 + CO_2 + H_2O](https://img.qammunity.org/2020/formulas/chemistry/high-school/u0q7i7fak61543cpqinyqh6k85n5kedrfu.png)
![CH_3COOH + NaHCO_3 ---> CH_3COONa + CO_2 + H_2O](https://img.qammunity.org/2020/formulas/chemistry/high-school/zvwk4rwl8cya9nar21u96e5jaddw2j26k4.png)
Step-by-step explanation:
Hydrocholoric acid is written as HCl
Calcium carbonate is written as
![CaCO_3](https://img.qammunity.org/2020/formulas/chemistry/middle-school/j52gwlpg6k9yrc48go7dzh3tenp8r0bn20.png)
For a balanced equation, 2 moles of Hydrochloric acid reacts with 1 mole of calcium carbonate to give one mole of calcium chloride, 1 mole of carbon dioxide and 1 mole of water respectively.
![2HCl + CaCO_3 ---> CaCl_2 + CO_2 + H_2O](https://img.qammunity.org/2020/formulas/chemistry/high-school/u0q7i7fak61543cpqinyqh6k85n5kedrfu.png)
Baking soda is written as
![NaHCO_3](https://img.qammunity.org/2020/formulas/chemistry/high-school/otvnyv004xae4ich99ob1gj5jxecn8dcre.png)
Vinegar is written as
![CH_3COOH](https://img.qammunity.org/2020/formulas/chemistry/middle-school/t6cgend8o59g8a88ixzmwyzhx7fgaguah4.png)
1 mole of vinegar reacts with 1 mole of baking soda to give 1 mole of sodium acetate, one mole of carbon dioxide and 1 mole of water respectively.
![CH_3COOH + NaHCO_3 ---> CH_3COONa + CO_2 + H_2O](https://img.qammunity.org/2020/formulas/chemistry/high-school/zvwk4rwl8cya9nar21u96e5jaddw2j26k4.png)