Question

Before a collision, a 50.0-kg object is moving at +5.0 m/s. Find the impulse that acted on the object if, after the collision, it moves at +17.0 m/s.

Answer 1

J=600 kg m/s

Step-by-step explanation:

Impulse And Momentum

Suppose a particle is moving at a certain speed
`v_1` and changes it to
`v_2`. The impulse J is equivalent to the change of linear momentum. The momentum can be computed by

`p=mv`

The initial and final momentums are given, respectively, by:

`p_1=mv_1,\ p_2=mv_2`

Thus, the change of momentum is

`\Delta p=p_2-p_1=m(v_2-v_1)`

It's equal to the Impulse J

`J=\Delta p`

`J=m(v_2-v_1)`

Our data is

`m=50\ kg,\ v_1=5\ m/s,\ v_2=17\ m/s`

`J=50\ (17-5)`

`J=600\ kg\ m/s`