130k views
3 votes
Let L1 be the line passing through the points Q1(−4, 4, 3) and Q2(0, 10, 1) and let L2 be the line passing through the point P1(3, 20, 0) with direction vector d=[3, −1, −2]T. Determine whether L1 and L2 intersect. If so, find the point of intersection Q.

User Fluxa
by
8.0k points

1 Answer

3 votes

Answer:

L1 and L2 do not intersect.

Explanation:

I am saying that the first line has the initial point Q1 and passes through the vector Q2 - Q1.

Q2 - Q1 = (0,10,1) - (-4,4,3) = (4,6,-2).

So the parametric equations for L1 are:


x(t) = -4 + 4t


y(t) = 4 + 6t


z(t) = 3 - 2t

For L2, we already have a point and the vector, so we can build the parametric equations:


x(t) = 3 + 3t


y(t) = 20 - t


z(t) = 0 - 2t

Now we must find the value of t for which x,y and z are equal. If all are equal at the same time t, these lines intersect at this instant of time.

So

x


-4 + 4t = 3 + 3t


t = 7

y


4 + 6t = 20 - t


7t = 16


t = 2....

Since the value of t when x are equal is different to when y are equal, these lines do not intersect.

User Reaz Patwary
by
8.4k points

Related questions

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.