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Let L1 be the line passing through the points Q1(−4, 4, 3) and Q2(0, 10, 1) and let L2 be the line passing through the point P1(3, 20, 0) with direction vector d=[3, −1, −2]T. Determine whether L1 and L2 intersect. If so, find the point of intersection Q.

User Fluxa
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1 Answer

3 votes

Answer:

L1 and L2 do not intersect.

Explanation:

I am saying that the first line has the initial point Q1 and passes through the vector Q2 - Q1.

Q2 - Q1 = (0,10,1) - (-4,4,3) = (4,6,-2).

So the parametric equations for L1 are:


x(t) = -4 + 4t


y(t) = 4 + 6t


z(t) = 3 - 2t

For L2, we already have a point and the vector, so we can build the parametric equations:


x(t) = 3 + 3t


y(t) = 20 - t


z(t) = 0 - 2t

Now we must find the value of t for which x,y and z are equal. If all are equal at the same time t, these lines intersect at this instant of time.

So

x


-4 + 4t = 3 + 3t


t = 7

y


4 + 6t = 20 - t


7t = 16


t = 2....

Since the value of t when x are equal is different to when y are equal, these lines do not intersect.

User Reaz Patwary
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7.9k points