Question

Two pellets, with charges q1 = 22 μC and q2 = 11 μC (1 μC = 10-6 C or 1 microCoulomb = 0.000001 Coulombs), are located 0.52 m apart.

(a) What is the electric force between them? in N(b) What mass object would experience this same force in the Earth's gravitational field? in kg

Answer 1

8.0 N

0.82 kg

Step-by-step explanation:

Given data

q₁ = 22 × 10⁻⁶ c

q₂ = 11 × 10⁻⁶ c

distance (r): 0.52 m

We can find the electrical force between these charges using he Coulomb's law.

`F=k_(e).(q_(1).q_(2))/(r^(2)) =8.99* 10^(9) N.m^(2).c^(-2) .(22 * 10^(-6)c . 11 * 10^(-6)c .)/((0.52m)^(2) ) =8.0N`

If the same force were experienced due to the gravitational field, we could find the value of mass associated with it using Newton's second law of motion.

F = m . g

8.0 N = m . 9.8 m/s²

m = 0.82 kg