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A wooden box weighing 150 N is sliding at a constant rate over a concrete sidewalk. The force required to pull the box at a steady rate is 78 N. What is the coefficient of friction?

A. 1.9
B. 228
C. 72
D. 0.52

User Ldam
by
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1 Answer

4 votes

Answer:D

Step-by-step explanation:

Given

Force required to move a box at steady rate is F=78 N

Weight of Block W=150 N

If the block is moving at a steady rate then net Force acting on it is zero

Applied Force must balance the Friction force


F=f_r


f_r=\mu N

where N=normal Reaction

Normal reaction must be equal to weight


\mu * 150=78


\mu =0.52

User Alexander Nenkov
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