Question

For the reaction N₂(g) + 3H₂(g) ⇌ 2NH₃(g) what is the value of Kc at 500 ∘C if the equilibrium concentrations are as follows:

[H₂] = 0.50 M , [N₂] = 0.50 M , and [NH₃] = 2.1 M ?
Express the equilibrium constant to two significant figures.

Answer 1

Kc = 70

Step-by-step explanation:

This is the reaction:

N₂(g) + 3H₂(g) ⇌ 2NH₃(g)

Let's make the expression for K, with concentration at equilibrium and in molarity.

Kc = [NH₃]² / [H₂]³ . [N₂]

Kc = (2.1)² / (0.5)³ . 0.5

Kc = 4.41 / 0.0625 → 70