Question

In a random sample of 9 cell​ phones, the mean full retail price was ​$546.70 and the standard deviation was ​$195.00. Further research suggests that the population mean is ​$428.87. Does the​ t-value for the original sample fall between minus−t 0.99 and st 0.99?​

Answer 1

`t_(stat) = 1.8127`

Explanation:

We are given the following in the question:

Population mean, μ = ​$428.87

Sample mean,
`\bar{x}` = ​​$546.70

Sample size, n = 9

Sample standard deviation, s = $195.00

Formula:

`t_(stat) = \displaystyle\frac{\bar{x} - \mu}{(\sigma)/(√(n)) }`

Putting all the values, we have

`t_(stat) = \displaystyle(546.7 - 428.87)/((195)/(√(9)) ) = 1.8127`

Thus, the t-value does not lie in the interval (-0.99,0.99)